I will be demonstrating
Lit 1 - I can accurately trace out the paths of light in ray diagrams
Lit 2 - I can locate images from mirrors and lenses using ray diagrams
Lit 3 - I can use light concepts to determine the size, characteristics from mirrors and lenses
Lit 4 - I can use mirror equation to determine location, character of images
Lit 5 - I can use Snell's law to predict the refraction of light
Lit 1 - I can accurately trace out the paths of light in ray diagrams
Lit 2 - I can locate images from mirrors and lenses using ray diagrams
Lit 3 - I can use light concepts to determine the size, characteristics from mirrors and lenses
Lit 4 - I can use mirror equation to determine location, character of images
Lit 5 - I can use Snell's law to predict the refraction of light
Question
If you place a 4.0 cm high luminous object 45 cm in front of a concave mirror with a focal length of 15 cm; determine
A) Where you must place a screen as to have a clear image of the object that others can see without looking in the mirror
B) Orientation
C) Height of the image
A) Where you must place a screen as to have a clear image of the object that others can see without looking in the mirror
B) Orientation
C) Height of the image
ResponseDiagram: The red lines represent the lights reflection on the concave mirror and where they would hit to get a reflected image. A parallel line hits the mirror and goes to the focal point. One line goes through the focal point and reflects parallel. One line goes through the curvature until it hits the mirror. So is the distance of the object to the mirror (45cm). The given focal point is 15 cm. The curvature is 2 times the focal point, so it's 30cm. si is unknown.
A) First use the mirror equation and plug in your values within. Use basic algebra and plug in your values for SO, SI, and F. Fill it in the mirror equation as (1/so)+(1/si)=(1/f) then you will get the answer for where the reflected image will be. In this equation you're trying to solve for SI. Which is the length of the reflected image to the mirror. B) Focal length and the concave mirror represent that hi is negative. And since hi is negative it is inverted. C) Use the magnification equation to solve for hi which is height of the reflected image. The magnification equation is represented as (-si/so) = (hi/ho) Use basic algebra to solve the equation. Plug in your values and you get hi= -2cm |
Problem #2
Light travels from air into an optical fiber with a refraction of 1.44
A) In which direction does the light bend?
B) If the angle of inference on the end of the fiber is 22 degrees, what is the angle of refraction inside the fiber?
C) Sketch the path of light as it changes media
A) In which direction does the light bend?
B) If the angle of inference on the end of the fiber is 22 degrees, what is the angle of refraction inside the fiber?
C) Sketch the path of light as it changes media
Diagram: N is the normal in which the light penetrates through and reflects at a different angle on another normal.
A) The normals are 1.00 for air and 1.44 for the optical fiber. Since the light to lower n to a denser n region it will bend light toward the normal. B) We will identify air as normal 1 and the fiber as the second normal. We will be using the angle of 22 degrees. Then use Snell's Law. n1(sintheta) = n2(sintheta) 1(sin22) = 1.44(sintheta) (sin22/1.44) = sin(theta) Sin(theta) = 15.07 degrees Therefore, it will be 15.07 degrees from the new normal. |