I will be demonstrating
Momentum 1 - I can calculate the momentum of an project/system with direction and proper units
Momentum 2 - I can use momentum conservation to solve different problems
Momentum 3 - I know the relationship between average force and rate of momentum transfer
Momentum 4 - I know the relationship between average force and time for a given momentum transfer (impulse)
Momentum 5 - I can use momentum transfer (impulse) to solve different problems
Momentum 1 - I can calculate the momentum of an project/system with direction and proper units
Momentum 2 - I can use momentum conservation to solve different problems
Momentum 3 - I know the relationship between average force and rate of momentum transfer
Momentum 4 - I know the relationship between average force and time for a given momentum transfer (impulse)
Momentum 5 - I can use momentum transfer (impulse) to solve different problems
IN a railroad yard, a train is being assembled. An empty boxcar, coasting at 3m/s, strikes a loaded car that is stationary, and the cars couple together. Each of the boxcars has a mass of 9000 kg when empty and the loaded car contains 5500kg of lumber.
Questions :
A. Complete the momentum conservation diagram
B. Momentum conservation equation
C. Find the speed of the coupled boxcars.
A. Complete the momentum conservation diagram
B. Momentum conservation equation
C. Find the speed of the coupled boxcars.
The event is that is stated, is that an empty box cart strikes a box cart that is loaded with lumber.
I designed a momentum conservation diagram. This is done by calculating the momentum which is m x v = p Initially, there are two different objects. Both with different massese and velocities. The empty box cart has a mass of 9000 kg and is traveling to the right in a positive direciton. The black bars drawn in the diagram indicate the motion of the empty box cart. It's momentum is calculated as m x v = p so 9000kg x 3m/s = 27,0000kgm/s is the momentum. It is the only moving object initially so it's seperate from the loaded box cart. The loaded cart has a velocity of 0m/s therefore it's momentum is 0kgm/s. The mass of the object is the mass of the kg the empty box car added to the lumber that is in it so the mass of the object is 9000 kg +55,000 kg = 64,000 kg. But since it's not moving it's 0kgm/s. Now that we found the initial velocity, object, and mass. We can now figure out the final momentum of the object when they "strike" each other. Because both objects collide with each other and are traveling together. They're both counted as one object travelling to the right. And because the law of momentum, the forces that were initially started with must be equal to the momentum after the collision. Therefore, we have the same amount of black bars in the initial as for the same for the final. To construct to the conservation of momentum, you take the velocity and mass of both objects. Question C is asking to find the speed of the cart when they've collided. Both momentums have to be qual. So if you add both of their masses you get 73000 kg with an unknown velocity. The units cancelled leaving m/s. And the velocity is .37m/s. Speed ignores direction and calculates where it'd be going. In this case, it'd be traveling to the right. |